Physics Numericals Chapter Wise (10+1 & 10+2)

Class 11 & Class 12 Physics – Numericals Book

CBSE + PSEB | Fully Solved | Chapter-wise

Table of Contents

  1. Class 11 Chapters
  2. Class 12 Chapters

Class 11 Physics – Chapter-wise Numericals

Chapter 2: Units & Measurements

  • Q1. Convert 5 m/s to km/h.
    Solution: 18 km/h
  • Q2. Find % error in 2.36 ± 0.05 cm.
    Solution: 2.12%
  • Q3. If X = a²b/√c, errors in a,b,c are 2%,3%,4%.
    Solution: 9%

Chapter 3: Motion in a Straight Line

  • Q1. Car accelerates at 2 m/s² for 5 s. Find v.
    Solution: 10 m/s
  • Q2. Stone dropped from 80 m. Find time.
    Solution: 4.04 s
  • Q3. v = 3t². Find displacement in 2 s.
    Solution: 8 m

Chapter 4: Motion in a Plane

  • Q1. Components of 10 N at 30°.
    Solution: 8.66 N, 5 N
  • Q2. Projectile at 20 m/s, 30°. Find range.
    Solution: 35.3 m
  • Q3. Projectile returns in 4 s. Find uy.
    Solution: 19.6 m/s

Chapter 5: Laws of Motion

  • Q1. Force 10 N on 2 kg. Find a.
    Solution: 5 m/s²
  • Q2. Two masses 4 kg & 6 kg. Find a, T.
    Solution: a = 1.96 m/s², T = 47.04 N
  • Q3. Bullet stops in 0.01 s. Find force.
    Solution: 600 N

Chapter 6: Work, Energy & Power

  • Q1. Work by 20 N over 5 m.
    Solution: 100 J
  • Q2. KE of 3 kg at 4 m/s.
    Solution: 24 J
  • Q3. Stone dropped from 20 m. Find v.
    Solution: 28 m/s

Chapter 7: System of Particles & Rotational Motion

  • Q1. COM of 2 kg at 0 m & 3 kg at 4 m.
    Solution: 2.4 m
  • Q2. MOI of rod (2 kg, 1 m).
    Solution: 0.167 kg·m²
  • Q3. Rolling disc KE.
    Solution: (3/4)Mv²

Chapter 8: Gravitation

  • Q1. Force between 10 kg & 20 kg at 2 m.
    Solution: 3.335×10⁻⁹ N
  • Q2. Escape velocity.
    Solution: 11.2 km/s
  • Q3. Planet 4× farther. Find T.
    Solution: 8 years

Chapter 9: Mechanical Properties of Solids

  • Q1. Stress for 500 N on 0.01 m².
    Solution: 5×10⁴ Pa
  • Q2. Young’s modulus.
    Solution: 1×10¹¹ Pa
  • Q3. Elastic energy = 0.05 J. Find F.
    Solution: 50 N

Chapter 10: Mechanical Properties of Fluids

  • Q1. Pressure at 20 m depth.
    Solution: 1.96×10⁵ Pa
  • Q2. Buoyant force for 0.02 m³.
    Solution: 196 N
  • Q3. Bernoulli pressure.
    Solution: 1.94×10⁵ Pa

Chapter 11: Thermal Properties of Matter

  • Q1. α from ΔL = 0.002 m.
    Solution: 2×10⁻⁵
  • Q2. Heat for 500 g water.
    Solution: 42000 J
  • Q3. Melt 2 kg ice.
    Solution: 6.68×10⁵ J

Chapter 12: Thermodynamics

  • Q1. Gas absorbs 500 J, does 200 J.
    Solution: ΔU = 300 J
  • Q2. Work at constant P.
    Solution: 400 J
  • Q3. Carnot efficiency.
    Solution: 50%

Chapter 13: Kinetic Theory

  • Q1. RMS speed at 300 K.
    Solution: 483 m/s
  • Q2. Mean free path.
    Solution: 2.5×10⁻⁸ m

Chapter 14: Oscillations

  • Q1. Spring time period.
    Solution: 0.314 s
  • Q2. vmax = ωA.
    Solution: 2 m/s

Chapter 15: Waves

  • Q1. Wave speed.
    Solution: 300 m/s
  • Q2. Beats.
    Solution: 4 Hz
  • Q3. Doppler shift.
    Solution: 531.25 Hz

Class 12 Physics – Chapter-wise Numericals

Chapter 1: Electric Charges & Fields

  • Q1. Force between 2 μC & 3 μC at 10 cm.
    Solution: 5.4 N
  • Q2. Field at 20 cm from 5 μC.
    Solution: 1.125×10⁶ N/C

Chapter 2: Electrostatic Potential & Capacitance

  • Q1. Potential at 10 cm from 2 μC.
    Solution: 1.8×10⁵ V
  • Q2. Energy stored in 10 μF at 200 V.
    Solution: 0.2 J

Chapter 3: Current Electricity

  • Q1. Drift velocity for I = 2 A.
    Solution: 6.25×10⁻⁴ m/s
  • Q2. Power in 10 Ω at 5 A.
    Solution: 250 W

Chapter 4: Moving Charges & Magnetism

  • Q1. Force on 2 C moving at 3 m/s in 0.5 T.
    Solution: 3 N
  • Q2. Radius of electron in 0.2 T.
    Solution: 2.84 mm

Chapter 5: Magnetism & Matter

  • Q1. Torque on dipole 0.5 A·m² in 0.2 T at 30°.
    Solution: 0.05 N·m

Chapter 6: Electromagnetic Induction

  • Q1. EMF when flux changes from 0.5 to 0.2 Wb in 0.1 s.
    Solution: 3 V

Chapter 7: Alternating Current

  • Q1. XL for L = 0.2 H at 50 Hz.
    Solution: 62.8 Ω
  • Q2. RMS value of 10 A peak.
    Solution: 7.07 A

Chapter 8: Electromagnetic Waves

  • Q1. Frequency of 600 nm light.
    Solution: 5×10¹⁴ Hz

Chapter 9: Ray Optics

  • Q1. Image distance for f = 20 cm, u = −30 cm.
    Solution: v = 60 cm

Chapter 10: Wave Optics

  • Q1. Fringe width for λ=600 nm, D=1 m, d=0.2 mm.
    Solution: 3 mm

Chapter 11: Dual Nature

  • Q1. λ for electron at 100 V.
    Solution: 0.123 nm

Chapter 12: Atoms

  • Q1. Energy of n=2 level.
    Solution: −3.4 eV

Chapter 13: Nuclei

  • Q1. Half-life for λ=0.01.
    Solution: 69.3 s

Chapter 14: Semiconductors

  • Q1. Current gain β = 100, IB = 20 μA.
    Solution: IC = 2 mA

Chapter 15: Communication Systems

  • Q1. Bandwidth for fm = 5 kHz.
    Solution: 10 kHz

End of Numericals Book

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